The advent of wide bandgap green synthesized copper zinc tin sulfide nanoparticles for applications in optical and electronic devices
1. UV-Vis spectroscopy dataset for the samples is determined and described in the excel file. The transmittance was recorded in percentage at different wavelengths of the UV-VIS characterization and the absorbance was determined using Beer’s law from the percentage transmittance data. 2. The other folder consists of the FTIR results of the samples.
Steps to reproduce
The steps to reproduce can be entirely found in the original manuscript, which is to be published. However, the following steps can also be followed for reproduction. The Vernonia amygdalina and Ocimum gratissimum leaves were separately washed using distilled water, dried at room temperature, and powdered using the mortal and pestle. 20 g each of the powdered leaves was dissolved in a container containing 20 cl acetone and 20 cl methanol. That is: Solution A: 20 g of Vernonia amygdalina + 20 cl acetone Solution B: 20 g of Vernonia amygdalina + 20 cl methanol Solution C: 20 g of Ocimum gratissimum + 20 cl acetone Solution D: 20 g of Ocimum gratissimum + 20 cl methanol The precursors, Thiourea Sodium Sulphate Anhydrous, Ammonia Solution, Zinc Nitrate (Zn(NO3)2.6H2O), Triethanolamine, Tin Sulphate, Copper (II) sulfate pentahydrate (CuSO4.5H2O) in 0.01 mol of each were dissolved in 10 ml of distilled water. The proportion of the precursor was obtained through the following mathematical equation; C_1=(C_2×V_2)/V_1 Where C_1 is the unknown concentration of the precursors in grams, C_2 is the known concentration of the precursors, gotten by: C_2 (concentration in gram)=molarity (concentration in Mol)×molar mass (concentration in g/mol). V_1 is the standard volume of 1000 ml, and V_2 is the known volume where the precursors are dissolved; it is the volume of the distilled water, thus V_2=10 ml. Proportions: 10 ml of Ammonia Solution and Triethanolamine; For Sodium Sulphate Anhydrous (Na2SO4), molar mass = 142.04 g/mol C_1=(0.01 mol ×142.04 g/mol×10ml)/(1000 ml)=0.014204 g For Zinc Nitrate (Zn(NO3)2.6H2O), molar mass = 297.48 g/mol C_1=(0.01 mol ×297.48 g/mol×10 ml)/(1000 ml)=0.029748 g For Thiourea, molar mass = 76.12 g/mol C_1=(0.01 mol ×76.12 g/mol×10 ml)/(1000 ml)=0.007612 g For Tin Sulphate, molar mass = 100 g/mol C_1=(0.01 mol ×100 g/mol×10 ml)/(1000 ml)=0.01 g For Copper (II) sulphate pentahydrate (CuSO4.5H2O), molar mass = 249.68 g/mol C_1=(0.01 mol ×249.68 g/mol×10 ml)/(1000 ml)=0.024968 g The solution consisting of the precursors in the above proportion, dissolved in 10 ml of distilled water, and stirred for proper dissolution is referred to as solution E. Sample F: it contains solution A plus 30 ml of solution E Sample G: it contains solution B plus 30 ml of solution E Sample H: it contains solution C plus 30 ml of solution E Sample I: contains solution D plus 30 ml of solution E The solutions F, G, H, and I was stirred for 90 minutes at 900C on the magnetic stirrer. Then, it was filtered, and the residue was allowed to dry. Thus, the dry residue of solutions F, G, H, and I is the synthesized CZTS.